Base | Representation |
---|---|
bin | 1011111011001111001011… |
… | …0101111111000001101011 |
3 | 1201102112011201220111111201 |
4 | 2332303302311333001223 |
5 | 3204313004443103301 |
6 | 43515414124305031 |
7 | 2522222242434043 |
oct | 276636265770153 |
9 | 51375151814451 |
10 | 13112314425451 |
11 | 41a59a0723a0a |
12 | 15793076a2177 |
13 | 74164180b427 |
14 | 3348d4750723 |
15 | 17b134a50201 |
hex | becf2d7f06b |
13112314425451 has 2 divisors, whose sum is σ = 13112314425452. Its totient is φ = 13112314425450.
The previous prime is 13112314425391. The next prime is 13112314425481. The reversal of 13112314425451 is 15452441321131.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (15452441321131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13112314425451 - 229 = 13111777554539 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13112314425451.
It is not a weakly prime, because it can be changed into another prime (13112314425481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556157212725 + 6556157212726.
It is an arithmetic number, because the mean of its divisors is an integer number (6556157212726).
Almost surely, 213112314425451 is an apocalyptic number.
13112314425451 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112314425451 is an equidigital number, since it uses as much as digits as its factorization.
13112314425451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 57600, while the sum is 37.
Adding to 13112314425451 its reverse (15452441321131), we get a palindrome (28564755746582).
The spelling of 13112314425451 in words is "thirteen trillion, one hundred twelve billion, three hundred fourteen million, four hundred twenty-five thousand, four hundred fifty-one".
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