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13112314425451 is a prime number
BaseRepresentation
bin1011111011001111001011…
…0101111111000001101011
31201102112011201220111111201
42332303302311333001223
53204313004443103301
643515414124305031
72522222242434043
oct276636265770153
951375151814451
1013112314425451
1141a59a0723a0a
1215793076a2177
1374164180b427
143348d4750723
1517b134a50201
hexbecf2d7f06b

13112314425451 has 2 divisors, whose sum is σ = 13112314425452. Its totient is φ = 13112314425450.

The previous prime is 13112314425391. The next prime is 13112314425481. The reversal of 13112314425451 is 15452441321131.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (15452441321131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13112314425451 - 229 = 13111777554539 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13112314425451.

It is not a weakly prime, because it can be changed into another prime (13112314425481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556157212725 + 6556157212726.

It is an arithmetic number, because the mean of its divisors is an integer number (6556157212726).

Almost surely, 213112314425451 is an apocalyptic number.

13112314425451 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112314425451 is an equidigital number, since it uses as much as digits as its factorization.

13112314425451 is an evil number, because the sum of its binary digits is even.

The product of its digits is 57600, while the sum is 37.

Adding to 13112314425451 its reverse (15452441321131), we get a palindrome (28564755746582).

The spelling of 13112314425451 in words is "thirteen trillion, one hundred twelve billion, three hundred fourteen million, four hundred twenty-five thousand, four hundred fifty-one".