131123255225051 has 4 divisors (see below), whose sum is σ = 131128247190072. Its totient is φ = 131118263260032.

The previous prime is 131123255225041. The next prime is 131123255225057. The reversal of 131123255225051 is 150522552321131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131123255225051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131123255224996 and 131123255225014.

It is not an unprimeable number, because it can be changed into a prime (131123255225057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2495943110 + ... + 2495995643.

It is an arithmetic number, because the mean of its divisors is an integer number (32782061797518).

Almost surely, 2^{131123255225051} is an apocalyptic number.

131123255225051 is a deficient number, since it is larger than the sum of its proper divisors (4991965021).

131123255225051 is an equidigital number, since it uses as much as digits as its factorization.

131123255225051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4991965020.

The product of its (nonzero) digits is 90000, while the sum is 38.

The spelling of 131123255225051 in words is "one hundred thirty-one trillion, one hundred twenty-three billion, two hundred fifty-five million, two hundred twenty-five thousand, fifty-one".