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13112330048003 is a prime number
BaseRepresentation
bin1011111011001111001111…
…0001100101001000000011
31201102112012211022012121202
42332303303301211020003
53204313022443014003
643515415443211415
72522222522301614
oct276636361451003
951375184265552
1013112330048003
1141a59a952440a
121579310976b6b
13741644b1b244
143348d6859c0b
1517b1360d9088
hexbecf3c65203

13112330048003 has 2 divisors, whose sum is σ = 13112330048004. Its totient is φ = 13112330048002.

The previous prime is 13112330047967. The next prime is 13112330048021. The reversal of 13112330048003 is 30084003321131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13112330048003 - 222 = 13112325853699 is a prime.

It is a super-3 number, since 3×131123300480033 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13112330048093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165024001 + 6556165024002.

It is an arithmetic number, because the mean of its divisors is an integer number (6556165024002).

Almost surely, 213112330048003 is an apocalyptic number.

13112330048003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112330048003 is an equidigital number, since it uses as much as digits as its factorization.

13112330048003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13112330048003 its reverse (30084003321131), we get a palindrome (43196333369134).

The spelling of 13112330048003 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, forty-eight thousand, three".