Base | Representation |
---|---|
bin | 1011111011001111001111… |
… | …0010100101010000101001 |
3 | 1201102112012211210112222011 |
4 | 2332303303302211100221 |
5 | 3204313023024420242 |
6 | 43515415452555521 |
7 | 2522222524444522 |
oct | 276636362452051 |
9 | 51375184715864 |
10 | 13112330310697 |
11 | 41a59a9693812 |
12 | 1579310a82ba1 |
13 | 741644bb0997 |
14 | 3348d68c7849 |
15 | 17b13613bd17 |
hex | becf3ca5429 |
13112330310697 has 2 divisors, whose sum is σ = 13112330310698. Its totient is φ = 13112330310696.
The previous prime is 13112330310659. The next prime is 13112330310701. The reversal of 13112330310697 is 79601303321131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8382623116176 + 4729707194521 = 2895276^2 + 2174789^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112330310697 is a prime.
It is a super-3 number, since 3×131123303106973 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13112330310097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165155348 + 6556165155349.
It is an arithmetic number, because the mean of its divisors is an integer number (6556165155349).
Almost surely, 213112330310697 is an apocalyptic number.
It is an amenable number.
13112330310697 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112330310697 is an equidigital number, since it uses as much as digits as its factorization.
13112330310697 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 40.
The spelling of 13112330310697 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, three hundred ten thousand, six hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •