Base | Representation |
---|---|
bin | 1011111011001111001111… |
… | …0010111001011011011111 |
3 | 1201102112012211221202021221 |
4 | 2332303303302321123133 |
5 | 3204313023040041221 |
6 | 43515415454434211 |
7 | 2522222525240422 |
oct | 276636362713337 |
9 | 51375184852257 |
10 | 13112330393311 |
11 | 41a59a973a896 |
12 | 1579310b02967 |
13 | 741644c0c476 |
14 | 3348d69099b9 |
15 | 17b136156541 |
hex | becf3cb96df |
13112330393311 has 2 divisors, whose sum is σ = 13112330393312. Its totient is φ = 13112330393310.
The previous prime is 13112330393257. The next prime is 13112330393347. The reversal of 13112330393311 is 11339303321131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13112330393311 - 233 = 13103740458719 is a prime.
It is a super-3 number, since 3×131123303933113 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112334393311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165196655 + 6556165196656.
It is an arithmetic number, because the mean of its divisors is an integer number (6556165196656).
Almost surely, 213112330393311 is an apocalyptic number.
13112330393311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112330393311 is an equidigital number, since it uses as much as digits as its factorization.
13112330393311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 34.
The spelling of 13112330393311 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, three hundred ninety-three thousand, three hundred eleven".
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