Base | Representation |
---|---|
bin | 11000011011000111… |
… | …00101010001001101 |
3 | 1020211211011112220101 |
4 | 30031203211101031 |
5 | 203323224132024 |
6 | 10005042451101 |
7 | 642635665141 |
oct | 141543452115 |
9 | 36754145811 |
10 | 13112333389 |
11 | 5619630171 |
12 | 265b363a91 |
13 | 130c74316c |
14 | 8c564b221 |
15 | 51b240c44 |
hex | 30d8e544d |
13112333389 has 2 divisors, whose sum is σ = 13112333390. Its totient is φ = 13112333388.
The previous prime is 13112333317. The next prime is 13112333417. The reversal of 13112333389 is 98333321131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13068376489 + 43956900 = 114317^2 + 6630^2 .
It is a cyclic number.
It is not a de Polignac number, because 13112333389 - 27 = 13112333261 is a prime.
It is a super-3 number, since 3×131123333893 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112933389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556166694 + 6556166695.
It is an arithmetic number, because the mean of its divisors is an integer number (6556166695).
Almost surely, 213112333389 is an apocalyptic number.
It is an amenable number.
13112333389 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112333389 is an equidigital number, since it uses as much as digits as its factorization.
13112333389 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34992, while the sum is 37.
The spelling of 13112333389 in words is "thirteen billion, one hundred twelve million, three hundred thirty-three thousand, three hundred eighty-nine".
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