13112400404031 has 8 divisors (see below), whose sum is σ = 17483284638720. Its totient is φ = 8741558219352.

The previous prime is 13112400404011. The next prime is 13112400404057. The reversal of 13112400404031 is 13040400421131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13112400404031 - 2⁹ = 13112400403519 is a prime.

It is a super-2 number, since 2×13112400404031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13112400403992 and 13112400404010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112400404011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9777561 + ... + 11037458.

It is an arithmetic number, because the mean of its divisors is an integer number (2185410579840).

Almost surely, 2^{13112400404031} is an apocalyptic number.

13112400404031 is a deficient number, since it is larger than the sum of its proper divisors (4370884234689).

13112400404031 is a wasteful number, since it uses less digits than its factorization.

13112400404031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21025005.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 13112400404031 its reverse (13040400421131), we get a palindrome (26152800825162).

The spelling of 13112400404031 in words is "thirteen trillion, one hundred twelve billion, four hundred million, four hundred four thousand, thirty-one".