Base | Representation |
---|---|
bin | 111101000011110011… |
… | …0110010011111100011 |
3 | 110112110021011000110211 |
4 | 1322013212302133203 |
5 | 4122020233030311 |
6 | 140123152434551 |
7 | 12321243361603 |
oct | 1720746623743 |
9 | 415407130424 |
10 | 131124111331 |
11 | 50678162664 |
12 | 214b5248a57 |
13 | c498a48075 |
14 | 64bc8c2c03 |
15 | 36268ad821 |
hex | 1e879b27e3 |
131124111331 has 2 divisors, whose sum is σ = 131124111332. Its totient is φ = 131124111330.
The previous prime is 131124111329. The next prime is 131124111343. The reversal of 131124111331 is 133111421131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131124111331 - 21 = 131124111329 is a prime.
It is a super-2 number, since 2×1311241113312 (a number of 23 digits) contains 22 as substring.
Together with 131124111329, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131124111031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65562055665 + 65562055666.
It is an arithmetic number, because the mean of its divisors is an integer number (65562055666).
Almost surely, 2131124111331 is an apocalyptic number.
131124111331 is a deficient number, since it is larger than the sum of its proper divisors (1).
131124111331 is an equidigital number, since it uses as much as digits as its factorization.
131124111331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 216, while the sum is 22.
Adding to 131124111331 its reverse (133111421131), we get a palindrome (264235532462).
The spelling of 131124111331 in words is "one hundred thirty-one billion, one hundred twenty-four million, one hundred eleven thousand, three hundred thirty-one".
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