Base | Representation |
---|---|
bin | 10011000101001100000… |
… | …111101111000000001000 |
3 | 11122100112201101101100022 |
4 | 103011030013233000020 |
5 | 132440410440334344 |
6 | 2442213141200012 |
7 | 163506542063120 |
oct | 23051407570010 |
9 | 4570481341308 |
10 | 1311242121224 |
11 | 466104aa2272 |
12 | 192164400008 |
13 | 9685a236289 |
14 | 47670683c80 |
15 | 24195d8e0ee |
hex | 1314c1ef008 |
1311242121224 has 64 divisors (see below), whose sum is σ = 2832348917760. Its totient is φ = 557453352960.
The previous prime is 1311242121181. The next prime is 1311242121307. The reversal of 1311242121224 is 4221212421131.
It is a super-2 number, since 2×13112421212242 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311242121193 and 1311242121202.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 86026244 + ... + 86041484.
It is an arithmetic number, because the mean of its divisors is an integer number (44255451840).
Almost surely, 21311242121224 is an apocalyptic number.
1311242121224 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
1311242121224 is an abundant number, since it is smaller than the sum of its proper divisors (1521106796536).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311242121224 is a wasteful number, since it uses less digits than its factorization.
1311242121224 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27478 (or 27474 counting only the distinct ones).
The product of its digits is 1536, while the sum is 26.
Adding to 1311242121224 its reverse (4221212421131), we get a palindrome (5532454542355).
The spelling of 1311242121224 in words is "one trillion, three hundred eleven billion, two hundred forty-two million, one hundred twenty-one thousand, two hundred twenty-four".
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