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1311242262051 = 3479299590511
BaseRepresentation
bin10011000101001100001…
…000010001011000100011
311122100112201122112112010
4103011030020101120203
5132440411004341201
62442213144204003
7163506543220521
oct23051410213043
94570481575463
101311242262051
11466105089057
12192164469603
139685a2853c7
14476706bd311
1524195dbabd6
hex1314c211623

1311242262051 has 8 divisors (see below), whose sum is σ = 1785521378304. Its totient is φ = 855562326920.

The previous prime is 1311242262041. The next prime is 1311242262119. The reversal of 1311242262051 is 1502622421131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1311242262051 - 25 = 1311242262019 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1311242262041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4649795115 + ... + 4649795396.

It is an arithmetic number, because the mean of its divisors is an integer number (223190172288).

Almost surely, 21311242262051 is an apocalyptic number.

1311242262051 is a deficient number, since it is larger than the sum of its proper divisors (474279116253).

1311242262051 is an equidigital number, since it uses as much as digits as its factorization.

1311242262051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9299590561.

The product of its (nonzero) digits is 5760, while the sum is 30.

Adding to 1311242262051 its reverse (1502622421131), we get a palindrome (2813864683182).

The spelling of 1311242262051 in words is "one trillion, three hundred eleven billion, two hundred forty-two million, two hundred sixty-two thousand, fifty-one".

Divisors: 1 3 47 141 9299590511 27898771533 437080754017 1311242262051