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1311242365619 is a prime number
BaseRepresentation
bin10011000101001100001…
…000101010101010110011
311122100112201211210120222
4103011030020222222303
5132440411021144434
62442213150323255
7163506544131464
oct23051410525263
94570481753528
101311242365619
1146610514994a
121921644b952b
139685a2c05a4
1447670708d6b
1524195ddb72e
hex1314c22aab3

1311242365619 has 2 divisors, whose sum is σ = 1311242365620. Its totient is φ = 1311242365618.

The previous prime is 1311242365607. The next prime is 1311242365621. The reversal of 1311242365619 is 9165632421131.

It is a strong prime.

It is an emirp because it is prime and its reverse (9165632421131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311242365619 is a prime.

It is a super-2 number, since 2×13112423656192 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1311242365621, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1311242365619.

It is not a weakly prime, because it can be changed into another prime (1311242365679) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655621182809 + 655621182810.

It is an arithmetic number, because the mean of its divisors is an integer number (655621182810).

Almost surely, 21311242365619 is an apocalyptic number.

1311242365619 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311242365619 is an equidigital number, since it uses as much as digits as its factorization.

1311242365619 is an evil number, because the sum of its binary digits is even.

The product of its digits is 233280, while the sum is 44.

The spelling of 1311242365619 in words is "one trillion, three hundred eleven billion, two hundred forty-two million, three hundred sixty-five thousand, six hundred nineteen".