Base | Representation |
---|---|
bin | 10011000101001100001… |
… | …001010011110100111010 |
3 | 11122100112202011100211210 |
4 | 103011030021103310322 |
5 | 132440411042043302 |
6 | 2442213154103550 |
7 | 163506545433126 |
oct | 23051411236472 |
9 | 4570482140753 |
10 | 1311242534202 |
11 | 466105254577 |
12 | 19216457abb6 |
13 | 9685a34c243 |
14 | 47670750586 |
15 | 24195e2166c |
hex | 1314c253d3a |
1311242534202 has 16 divisors (see below), whose sum is σ = 2760510598560. Its totient is φ = 414076589712.
The previous prime is 1311242534201. The next prime is 1311242534213. The reversal of 1311242534202 is 2024352421131.
It is a happy number.
It is a self number, because there is not a number n which added to its sum of digits gives 1311242534202.
It is not an unprimeable number, because it can be changed into a prime (1311242534201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5751063633 + ... + 5751063860.
It is an arithmetic number, because the mean of its divisors is an integer number (172531912410).
Almost surely, 21311242534202 is an apocalyptic number.
1311242534202 is an abundant number, since it is smaller than the sum of its proper divisors (1449268064358).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311242534202 is a wasteful number, since it uses less digits than its factorization.
1311242534202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11502127517.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 1311242534202 its reverse (2024352421131), we get a palindrome (3335594955333).
The spelling of 1311242534202 in words is "one trillion, three hundred eleven billion, two hundred forty-two million, five hundred thirty-four thousand, two hundred two".
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