Base | Representation |
---|---|
bin | 1011111011001111100111… |
… | …1111110110110111010101 |
3 | 1201102112111002202120200112 |
4 | 2332303321333312313111 |
5 | 3204313231210011343 |
6 | 43515434053052405 |
7 | 2522225230604321 |
oct | 276637177666725 |
9 | 51375432676615 |
10 | 13112434453973 |
11 | 41a5a52455138 |
12 | 157933b927105 |
13 | 74166064531a |
14 | 334906676981 |
15 | 17b14035e218 |
hex | becf9ff6dd5 |
13112434453973 has 2 divisors, whose sum is σ = 13112434453974. Its totient is φ = 13112434453972.
The previous prime is 13112434453961. The next prime is 13112434454057. The reversal of 13112434453973 is 37935443421131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12921271376689 + 191163077284 = 3594617^2 + 437222^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112434453973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112439453973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556217226986 + 6556217226987.
It is an arithmetic number, because the mean of its divisors is an integer number (6556217226987).
Almost surely, 213112434453973 is an apocalyptic number.
It is an amenable number.
13112434453973 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112434453973 is an equidigital number, since it uses as much as digits as its factorization.
13112434453973 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3265920, while the sum is 50.
The spelling of 13112434453973 in words is "thirteen trillion, one hundred twelve billion, four hundred thirty-four million, four hundred fifty-three thousand, nine hundred seventy-three".
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