Base | Representation |
---|---|
bin | 1011111011001111101001… |
… | …0101111110000000100011 |
3 | 1201102112111111200001220010 |
4 | 2332303322111332000203 |
5 | 3204313234201003103 |
6 | 43515434421220003 |
7 | 2522225331065454 |
oct | 276637225760043 |
9 | 51375444601803 |
10 | 13112440250403 |
11 | 41a5a5575407a |
12 | 1579341861603 |
13 | 7416618c4770 |
14 | 33490734512b |
15 | 17b140b06903 |
hex | becfa57e023 |
13112440250403 has 32 divisors (see below), whose sum is σ = 18939431976192. Its totient is φ = 8021629123200.
The previous prime is 13112440250401. The next prime is 13112440250467. The reversal of 13112440250403 is 30405204421131.
It is not a de Polignac number, because 13112440250403 - 21 = 13112440250401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13112440250401) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3015793 + ... + 5943053.
It is an arithmetic number, because the mean of its divisors is an integer number (591857249256).
Almost surely, 213112440250403 is an apocalyptic number.
13112440250403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13112440250403 is a deficient number, since it is larger than the sum of its proper divisors (5826991725789).
13112440250403 is a wasteful number, since it uses less digits than its factorization.
13112440250403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2927955.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 13112440250403 its reverse (30405204421131), we get a palindrome (43517644671534).
The spelling of 13112440250403 in words is "thirteen trillion, one hundred twelve billion, four hundred forty million, two hundred fifty thousand, four hundred three".
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