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1311253613353 is a prime number
BaseRepresentation
bin10011000101001100110…
…011100100101100101001
311122100120112000020120201
4103011030303210230221
5132440421411111403
62442214231352201
7163510041545635
oct23051463445451
94570515006521
101311253613353
114661105314a2
12192168222661
139685c72b058
1447671dd5dc5
1524196dae21d
hex1314cce4b29

1311253613353 has 2 divisors, whose sum is σ = 1311253613354. Its totient is φ = 1311253613352.

The previous prime is 1311253613323. The next prime is 1311253613357. The reversal of 1311253613353 is 3533163521131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1301452019344 + 9801594009 = 1140812^2 + 99003^2 .

It is an emirp because it is prime and its reverse (3533163521131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311253613353 - 29 = 1311253612841 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311253613357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655626806676 + 655626806677.

It is an arithmetic number, because the mean of its divisors is an integer number (655626806677).

Almost surely, 21311253613353 is an apocalyptic number.

It is an amenable number.

1311253613353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311253613353 is an equidigital number, since it uses as much as digits as its factorization.

1311253613353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 72900, while the sum is 37.

The spelling of 1311253613353 in words is "one trillion, three hundred eleven billion, two hundred fifty-three million, six hundred thirteen thousand, three hundred fifty-three".