1311254025577 has 2 divisors, whose sum is σ = 1311254025578. Its totient is φ = 1311254025576.

The previous prime is 1311254025551. The next prime is 1311254025583. The reversal of 1311254025577 is 7755204521131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1300274967616 + 10979057961 = 1140296^2 + 104781^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311254025577 - 2¹¹ = 1311254023529 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311254029577) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655627012788 + 655627012789.

It is an arithmetic number, because the mean of its divisors is an integer number (655627012789).

Almost surely, 2^{1311254025577} is an apocalyptic number.

It is an amenable number.

1311254025577 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311254025577 is an equidigital number, since it uses as much as digits as its factorization.

1311254025577 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 294000, while the sum is 43.

The spelling of 1311254025577 in words is "one trillion, three hundred eleven billion, two hundred fifty-four million, twenty-five thousand, five hundred seventy-seven".