Base | Representation |
---|---|
bin | 10011000101001100110… |
… | …101001001010101001111 |
3 | 11122100120112210012000022 |
4 | 103011030311021111033 |
5 | 132440422012304201 |
6 | 2442214244252355 |
7 | 163510045213451 |
oct | 23051465112517 |
9 | 4570515705008 |
10 | 1311254025551 |
11 | 466110793158 |
12 | 1921683a10bb |
13 | 9685c843862 |
14 | 476720a22d1 |
15 | 24196e4141b |
hex | 1314cd4954f |
1311254025551 has 2 divisors, whose sum is σ = 1311254025552. Its totient is φ = 1311254025550.
The previous prime is 1311254025511. The next prime is 1311254025577. The reversal of 1311254025551 is 1555204521131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311254025551 - 214 = 1311254009167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311254025511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655627012775 + 655627012776.
It is an arithmetic number, because the mean of its divisors is an integer number (655627012776).
Almost surely, 21311254025551 is an apocalyptic number.
1311254025551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311254025551 is an equidigital number, since it uses as much as digits as its factorization.
1311254025551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30000, while the sum is 35.
Adding to 1311254025551 its reverse (1555204521131), we get a palindrome (2866458546682).
The spelling of 1311254025551 in words is "one trillion, three hundred eleven billion, two hundred fifty-four million, twenty-five thousand, five hundred fifty-one".
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