Base | Representation |
---|---|
bin | 10011000101001100110… |
… | …101001001011010101101 |
3 | 11122100120112210012111021 |
4 | 103011030311021122231 |
5 | 132440422012312101 |
6 | 2442214244254141 |
7 | 163510045214461 |
oct | 23051465113255 |
9 | 4570515705437 |
10 | 1311254025901 |
11 | 466110793446 |
12 | 1921683a1351 |
13 | 9685c843a71 |
14 | 476720a24a1 |
15 | 24196e415a1 |
hex | 1314cd496ad |
1311254025901 has 2 divisors, whose sum is σ = 1311254025902. Its totient is φ = 1311254025900.
The previous prime is 1311254025821. The next prime is 1311254026063. The reversal of 1311254025901 is 1095204521131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 951102810025 + 360151215876 = 975245^2 + 600126^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311254025901 - 27 = 1311254025773 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311254085901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655627012950 + 655627012951.
It is an arithmetic number, because the mean of its divisors is an integer number (655627012951).
Almost surely, 21311254025901 is an apocalyptic number.
It is an amenable number.
1311254025901 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311254025901 is an equidigital number, since it uses as much as digits as its factorization.
1311254025901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 34.
The spelling of 1311254025901 in words is "one trillion, three hundred eleven billion, two hundred fifty-four million, twenty-five thousand, nine hundred one".
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