Base | Representation |
---|---|
bin | 10011000101001100111… |
… | …000111111111000110011 |
3 | 11122100120121200111022201 |
4 | 103011030320333320303 |
5 | 132440422242113233 |
6 | 2442214322044031 |
7 | 163510056620653 |
oct | 23051470777063 |
9 | 4570517614281 |
10 | 1311255035443 |
11 | 466111312981 |
12 | 1921687a9617 |
13 | 9685cb08422 |
14 | 47672286363 |
15 | 2419709077d |
hex | 1314ce3fe33 |
1311255035443 has 2 divisors, whose sum is σ = 1311255035444. Its totient is φ = 1311255035442.
The previous prime is 1311255035341. The next prime is 1311255035479. The reversal of 1311255035443 is 3445305521131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311255035443 - 217 = 1311254904371 is a prime.
It is a super-3 number, since 3×13112550354433 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1311255035483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655627517721 + 655627517722.
It is an arithmetic number, because the mean of its divisors is an integer number (655627517722).
Almost surely, 21311255035443 is an apocalyptic number.
1311255035443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311255035443 is an equidigital number, since it uses as much as digits as its factorization.
1311255035443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108000, while the sum is 37.
The spelling of 1311255035443 in words is "one trillion, three hundred eleven billion, two hundred fifty-five million, thirty-five thousand, four hundred forty-three".
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