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13112553542340 = 223572331277158077
BaseRepresentation
bin1011111011010000000100…
…0110001001001011000100
31201102112210101211220012210
42332310001012021023010
53204314002201323330
643515453545343420
72522231205050610
oct276640106111304
951375711756183
1013112553542340
1141a60036a3a7a
121579373797b70
1374167c210305
143349183d6340
1517b14aa348b0
hexbed011892c4

13112553542340 has 384 divisors, whose sum is σ = 45360383459328. Its totient is φ = 2764331919360.

The previous prime is 13112553542261. The next prime is 13112553542359. The reversal of 13112553542340 is 4324535521131.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 82871382 + ... + 83029458.

It is an arithmetic number, because the mean of its divisors is an integer number (118125998592).

Almost surely, 213112553542340 is an apocalyptic number.

13112553542340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13112553542340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22680191729664).

13112553542340 is an abundant number, since it is smaller than the sum of its proper divisors (32247829916988).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112553542340 is a wasteful number, since it uses less digits than its factorization.

13112553542340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 158427 (or 158425 counting only the distinct ones).

The product of its (nonzero) digits is 216000, while the sum is 39.

The spelling of 13112553542340 in words is "thirteen trillion, one hundred twelve billion, five hundred fifty-three million, five hundred forty-two thousand, three hundred forty".