Base | Representation |
---|---|
bin | 10011000101001100111… |
… | …010111001010111000101 |
3 | 11122100120122121202211122 |
4 | 103011030322321113011 |
5 | 132440422404023442 |
6 | 2442214340443325 |
7 | 163510064062364 |
oct | 23051472712705 |
9 | 4570518552748 |
10 | 1311255532997 |
11 | 466111622783 |
12 | 1921689a9545 |
13 | 9685cc50a37 |
14 | 476723757db |
15 | 2419713cdd2 |
hex | 1314ceb95c5 |
1311255532997 has 2 divisors, whose sum is σ = 1311255532998. Its totient is φ = 1311255532996.
The previous prime is 1311255532991. The next prime is 1311255533023. The reversal of 1311255532997 is 7992355521131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1257804867361 + 53450665636 = 1121519^2 + 231194^2 .
It is an emirp because it is prime and its reverse (7992355521131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311255532997 - 26 = 1311255532933 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311255532991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655627766498 + 655627766499.
It is an arithmetic number, because the mean of its divisors is an integer number (655627766499).
Almost surely, 21311255532997 is an apocalyptic number.
It is an amenable number.
1311255532997 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311255532997 is an equidigital number, since it uses as much as digits as its factorization.
1311255532997 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2551500, while the sum is 53.
The spelling of 1311255532997 in words is "one trillion, three hundred eleven billion, two hundred fifty-five million, five hundred thirty-two thousand, nine hundred ninety-seven".
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