Base | Representation |
---|---|
bin | 10011000101001100111… |
… | …110111110101011010111 |
3 | 11122100120201122011002101 |
4 | 103011030332332223113 |
5 | 132440423142301401 |
6 | 2442214415422531 |
7 | 163510106141062 |
oct | 23051476765327 |
9 | 4570521564071 |
10 | 1311256603351 |
11 | 466112193972 |
12 | 192169224a47 |
13 | 96860236c96 |
14 | 476725738d9 |
15 | 241972a0101 |
hex | 1314cfbead7 |
1311256603351 has 4 divisors (see below), whose sum is σ = 1332752613304. Its totient is φ = 1289760593400.
The previous prime is 1311256603339. The next prime is 1311256603367. The reversal of 1311256603351 is 1533066521131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1311256603351 - 227 = 1311122385623 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1311256603351.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311256601351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10748004885 + ... + 10748005006.
It is an arithmetic number, because the mean of its divisors is an integer number (333188153326).
Almost surely, 21311256603351 is an apocalyptic number.
1311256603351 is a deficient number, since it is larger than the sum of its proper divisors (21496009953).
1311256603351 is an equidigital number, since it uses as much as digits as its factorization.
1311256603351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21496009952.
The product of its (nonzero) digits is 48600, while the sum is 37.
The spelling of 1311256603351 in words is "one trillion, three hundred eleven billion, two hundred fifty-six million, six hundred three thousand, three hundred fifty-one".
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