Base | Representation |
---|---|
bin | 11000011011001001… |
… | …01101001101010001 |
3 | 1020211211201112002201 |
4 | 30031210231031101 |
5 | 203323313044144 |
6 | 10005053043201 |
7 | 642641333203 |
oct | 141544551521 |
9 | 36754645081 |
10 | 13112628049 |
11 | 5619811594 |
12 | 265b486501 |
13 | 130c817311 |
14 | 8c56c6773 |
15 | 51b29d1d4 |
hex | 30d92d351 |
13112628049 has 4 divisors (see below), whose sum is σ = 13682742336. Its totient is φ = 12542513764.
The previous prime is 13112628019. The next prime is 13112628059. The reversal of 13112628049 is 94082621131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13112628049 - 25 = 13112628017 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13112627999 and 13112628017.
It is not an unprimeable number, because it can be changed into a prime (13112628019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285057109 + ... + 285057154.
It is an arithmetic number, because the mean of its divisors is an integer number (3420685584).
Almost surely, 213112628049 is an apocalyptic number.
It is an amenable number.
13112628049 is a deficient number, since it is larger than the sum of its proper divisors (570114287).
13112628049 is an equidigital number, since it uses as much as digits as its factorization.
13112628049 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 570114286.
The product of its (nonzero) digits is 20736, while the sum is 37.
The spelling of 13112628049 in words is "thirteen billion, one hundred twelve million, six hundred twenty-eight thousand, forty-nine".
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