Base | Representation |
---|---|
bin | 11000011011001001… |
… | …10011100111111101 |
3 | 1020211211202212011012 |
4 | 30031210303213331 |
5 | 203323314414313 |
6 | 10005053405005 |
7 | 642641502632 |
oct | 141544634775 |
9 | 36754685135 |
10 | 13112654333 |
11 | 561982a309 |
12 | 265b499765 |
13 | 130c82627c |
14 | 8c56d2189 |
15 | 51b2a5da8 |
hex | 30d9339fd |
13112654333 has 4 divisors (see below), whose sum is σ = 13112885820. Its totient is φ = 13112422848.
The previous prime is 13112654293. The next prime is 13112654411. The reversal of 13112654333 is 33345621131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6945222244 + 6167432089 = 83338^2 + 78533^2 .
It is a cyclic number.
It is not a de Polignac number, because 13112654333 - 232 = 8817687037 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13112654333.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13112657333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32603 + ... + 165191.
It is an arithmetic number, because the mean of its divisors is an integer number (3278221455).
Almost surely, 213112654333 is an apocalyptic number.
It is an amenable number.
13112654333 is a deficient number, since it is larger than the sum of its proper divisors (231487).
13112654333 is an equidigital number, since it uses as much as digits as its factorization.
13112654333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 231486.
The product of its digits is 19440, while the sum is 32.
The spelling of 13112654333 in words is "thirteen billion, one hundred twelve million, six hundred fifty-four thousand, three hundred thirty-three".
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