13113002011 has 2 divisors, whose sum is σ = 13113002012. Its totient is φ = 13113002010.

The previous prime is 13113001987. The next prime is 13113002041. The reversal of 13113002011 is 11020031131.

It is a weak prime.

It is an emirp because it is prime and its reverse (11020031131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13113002011 - 2¹³ = 13112993819 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13113001982 and 13113002000.

It is not a weakly prime, because it can be changed into another prime (13113002041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556501005 + 6556501006.

It is an arithmetic number, because the mean of its divisors is an integer number (6556501006).

Almost surely, 2^13113002011 is an apocalyptic number.

13113002011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113002011 is an equidigital number, since it uses as much as digits as its factorization.

13113002011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 13113002011 its reverse (11020031131), we get a palindrome (24133033142).

The spelling of 13113002011 in words is "thirteen billion, one hundred thirteen million, two thousand, eleven".