Base | Representation |
---|---|
bin | 111101000011111110… |
… | …1010111110001111111 |
3 | 110112110200021210001101 |
4 | 1322013331113301333 |
5 | 4122023241444411 |
6 | 140123523353531 |
7 | 12321344606023 |
oct | 1720775276177 |
9 | 415420253041 |
10 | 131130031231 |
11 | 50680536341 |
12 | 214b72228a7 |
13 | c49a03b774 |
14 | 64bd5c4383 |
15 | 362717c8c1 |
hex | 1e87f57c7f |
131130031231 has 2 divisors, whose sum is σ = 131130031232. Its totient is φ = 131130031230.
The previous prime is 131130031211. The next prime is 131130031247. The reversal of 131130031231 is 132130031131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131130031231 - 27 = 131130031103 is a prime.
It is a super-2 number, since 2×1311300312312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131130031199 and 131130031208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131130031211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65565015615 + 65565015616.
It is an arithmetic number, because the mean of its divisors is an integer number (65565015616).
Almost surely, 2131130031231 is an apocalyptic number.
131130031231 is a deficient number, since it is larger than the sum of its proper divisors (1).
131130031231 is an equidigital number, since it uses as much as digits as its factorization.
131130031231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 131130031231 its reverse (132130031131), we get a palindrome (263260062362).
The spelling of 131130031231 in words is "one hundred thirty-one billion, one hundred thirty million, thirty-one thousand, two hundred thirty-one".
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