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1311301444223 = 8315798812581
BaseRepresentation
bin10011000101001111101…
…010000010001001111111
311122100200212000022012102
4103011033222002021333
5132441021132203343
62442223100455315
7163511162240351
oct23051752021177
94570625008172
101311301444223
11466135530541
1219218024a53b
1396869607044
14476784c70d1
152419b1ab3b8
hex1314fa8227f

1311301444223 has 4 divisors (see below), whose sum is σ = 1327100256888. Its totient is φ = 1295502631560.

The previous prime is 1311301444183. The next prime is 1311301444267. The reversal of 1311301444223 is 3224441031131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311301444223 - 216 = 1311301378687 is a prime.

It is a super-2 number, since 2×13113014442232 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311301444283) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7899406208 + ... + 7899406373.

It is an arithmetic number, because the mean of its divisors is an integer number (331775064222).

Almost surely, 21311301444223 is an apocalyptic number.

1311301444223 is a deficient number, since it is larger than the sum of its proper divisors (15798812665).

1311301444223 is an equidigital number, since it uses as much as digits as its factorization.

1311301444223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15798812664.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1311301444223 its reverse (3224441031131), we get a palindrome (4535742475354).

The spelling of 1311301444223 in words is "one trillion, three hundred eleven billion, three hundred one million, four hundred forty-four thousand, two hundred twenty-three".

Divisors: 1 83 15798812581 1311301444223