1311302225333 has 4 divisors (see below), whose sum is σ = 1315263863808. Its totient is φ = 1307340586860.

The previous prime is 1311302225297. The next prime is 1311302225347. The reversal of 1311302225333 is 3335222031131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311302225333 - 2¹⁴ = 1311302208949 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311302225296 and 1311302225305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311302225353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1980818741 + ... + 1980819402.

It is an arithmetic number, because the mean of its divisors is an integer number (328815965952).

Almost surely, 2^{1311302225333} is an apocalyptic number.

It is an amenable number.

1311302225333 is a deficient number, since it is larger than the sum of its proper divisors (3961638475).

1311302225333 is an equidigital number, since it uses as much as digits as its factorization.

1311302225333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3961638474.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 1311302225333 its reverse (3335222031131), we get a palindrome (4646524256464).

The spelling of 1311302225333 in words is "one trillion, three hundred eleven billion, three hundred two million, two hundred twenty-five thousand, three hundred thirty-three".