Base | Representation |
---|---|
bin | 11000011011001100… |
… | …01111010111011111 |
3 | 1020211212110221121220 |
4 | 30031212033113133 |
5 | 203323413430421 |
6 | 10005105424423 |
7 | 642644626326 |
oct | 141546172737 |
9 | 36755427556 |
10 | 13113030111 |
11 | 5619a66675 |
12 | 265b63b113 |
13 | 130c92831c |
14 | 8c578d0bd |
15 | 51b32c3c6 |
hex | 30d98f5df |
13113030111 has 4 divisors (see below), whose sum is σ = 17484040152. Its totient is φ = 8742020072.
The previous prime is 13113030083. The next prime is 13113030149. The reversal of 13113030111 is 11103031131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11103031131 = 3 ⋅3701010377.
It is a cyclic number.
It is not a de Polignac number, because 13113030111 - 27 = 13113029983 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13113030011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185505016 + ... + 2185505021.
It is an arithmetic number, because the mean of its divisors is an integer number (4371010038).
Almost surely, 213113030111 is an apocalyptic number.
13113030111 is a deficient number, since it is larger than the sum of its proper divisors (4371010041).
13113030111 is an equidigital number, since it uses as much as digits as its factorization.
13113030111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4371010040.
The product of its (nonzero) digits is 27, while the sum is 15.
Adding to 13113030111 its reverse (11103031131), we get a palindrome (24216061242).
The spelling of 13113030111 in words is "thirteen billion, one hundred thirteen million, thirty thousand, one hundred eleven".
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