Base | Representation |
---|---|
bin | 1011111011010001110110… |
… | …0011100010011011010011 |
3 | 1201102121000200021202201022 |
4 | 2332310131203202123103 |
5 | 3204320441414310003 |
6 | 43520013203230055 |
7 | 2522246063340611 |
oct | 276643543423323 |
9 | 51377020252638 |
10 | 13113031010003 |
11 | 41a6229170551 |
12 | 157948767832b |
13 | 741727106462 |
14 | 3349619a46b1 |
15 | 17b1778eb738 |
hex | bed1d8e26d3 |
13113031010003 has 4 divisors (see below), whose sum is σ = 13113220057920. Its totient is φ = 13112841962088.
The previous prime is 13113031009993. The next prime is 13113031010033. The reversal of 13113031010003 is 30001013031131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13113031010003 - 226 = 13112963901139 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13113031010033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94419875 + ... + 94558652.
It is an arithmetic number, because the mean of its divisors is an integer number (3278305014480).
Almost surely, 213113031010003 is an apocalyptic number.
13113031010003 is a deficient number, since it is larger than the sum of its proper divisors (189047917).
13113031010003 is an equidigital number, since it uses as much as digits as its factorization.
13113031010003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 189047916.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 13113031010003 its reverse (30001013031131), we get a palindrome (43114044041134).
The spelling of 13113031010003 in words is "thirteen trillion, one hundred thirteen billion, thirty-one million, ten thousand, three".
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