Base | Representation |
---|---|
bin | 10011000101001111110… |
… | …100101000010101000111 |
3 | 11122100201001020102121220 |
4 | 103011033310220111013 |
5 | 132441022340101043 |
6 | 2442223240211423 |
7 | 163511224660035 |
oct | 23051764502507 |
9 | 4570631212556 |
10 | 1311304222023 |
11 | 466137058544 |
12 | 192181169b73 |
13 | 9686a06a503 |
14 | 47678a0b555 |
15 | 2419b559483 |
hex | 1314fd28547 |
1311304222023 has 8 divisors (see below), whose sum is σ = 1748410993536. Its totient is φ = 874200132600.
The previous prime is 1311304222003. The next prime is 1311304222027. The reversal of 1311304222023 is 3202224031131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1311304222023 - 25 = 1311304221991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311304221984 and 1311304222002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311304222027) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1285038 + ... + 2067348.
It is an arithmetic number, because the mean of its divisors is an integer number (218551374192).
Almost surely, 21311304222023 is an apocalyptic number.
1311304222023 is a deficient number, since it is larger than the sum of its proper divisors (437106771513).
1311304222023 is an equidigital number, since it uses as much as digits as its factorization.
1311304222023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1341045.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 1311304222023 its reverse (3202224031131), we get a palindrome (4513528253154).
The spelling of 1311304222023 in words is "one trillion, three hundred eleven billion, three hundred four million, two hundred twenty-two thousand, twenty-three".
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