Base | Representation |
---|---|
bin | 1011111011010001111101… |
… | …0110000010101000001111 |
3 | 1201102121002202202202100201 |
4 | 2332310133112002220033 |
5 | 3204321022110320234 |
6 | 43520020154434331 |
7 | 2522246606435002 |
oct | 276643726025017 |
9 | 51377082682321 |
10 | 13113061026319 |
11 | 41a6244102221 |
12 | 15794957329a7 |
13 | 7417303b59a7 |
14 | 334965979539 |
15 | 17b17a37a314 |
hex | bed1f582a0f |
13113061026319 has 2 divisors, whose sum is σ = 13113061026320. Its totient is φ = 13113061026318.
The previous prime is 13113061026281. The next prime is 13113061026433. The reversal of 13113061026319 is 91362016031131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13113061026319 - 221 = 13113058929167 is a prime.
It is a super-2 number, since 2×131130610263192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13113061726319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556530513159 + 6556530513160.
It is an arithmetic number, because the mean of its divisors is an integer number (6556530513160).
Almost surely, 213113061026319 is an apocalyptic number.
13113061026319 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113061026319 is an equidigital number, since it uses as much as digits as its factorization.
13113061026319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 37.
The spelling of 13113061026319 in words is "thirteen trillion, one hundred thirteen billion, sixty-one million, twenty-six thousand, three hundred nineteen".
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