Base | Representation |
---|---|
bin | 111101000011111111… |
… | …1101100111101010111 |
3 | 110112110201102211020012 |
4 | 1322013333230331113 |
5 | 4122023421023023 |
6 | 140123544430435 |
7 | 12321353032325 |
oct | 1720777547527 |
9 | 415421384205 |
10 | 131130642263 |
11 | 50680913425 |
12 | 214b747841b |
13 | c49a1c391a |
14 | 64bd702d15 |
15 | 362724d978 |
hex | 1e87fecf57 |
131130642263 has 2 divisors, whose sum is σ = 131130642264. Its totient is φ = 131130642262.
The previous prime is 131130642259. The next prime is 131130642311. The reversal of 131130642263 is 362246031131.
It is a weak prime.
It is an emirp because it is prime and its reverse (362246031131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131130642263 - 22 = 131130642259 is a prime.
It is a super-2 number, since 2×1311306422632 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131130644263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65565321131 + 65565321132.
It is an arithmetic number, because the mean of its divisors is an integer number (65565321132).
Almost surely, 2131130642263 is an apocalyptic number.
131130642263 is a deficient number, since it is larger than the sum of its proper divisors (1).
131130642263 is an equidigital number, since it uses as much as digits as its factorization.
131130642263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 131130642263 its reverse (362246031131), we get a palindrome (493376673394).
The spelling of 131130642263 in words is "one hundred thirty-one billion, one hundred thirty million, six hundred forty-two thousand, two hundred sixty-three".
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