Base | Representation |
---|---|
bin | 11000011011001101… |
… | …00000101011101001 |
3 | 1020211212121112220122 |
4 | 30031212200223221 |
5 | 203323423213113 |
6 | 10005111133025 |
7 | 642645343154 |
oct | 141546405351 |
9 | 36755545818 |
10 | 13113101033 |
11 | 561a00498a |
12 | 265b674175 |
13 | 130c9516a6 |
14 | 8c57aac9b |
15 | 51b343408 |
hex | 30d9a0ae9 |
13113101033 has 4 divisors (see below), whose sum is σ = 13292732628. Its totient is φ = 12933469440.
The previous prime is 13113100997. The next prime is 13113101063. The reversal of 13113101033 is 33010131131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33010131131 = 51407 ⋅642133.
It can be written as a sum of positive squares in 2 ways, for example, as 4809699904 + 8303401129 = 69352^2 + 91123^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13113101033 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13113101063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89815688 + ... + 89815833.
It is an arithmetic number, because the mean of its divisors is an integer number (3323183157).
Almost surely, 213113101033 is an apocalyptic number.
It is an amenable number.
13113101033 is a deficient number, since it is larger than the sum of its proper divisors (179631595).
13113101033 is an equidigital number, since it uses as much as digits as its factorization.
13113101033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179631594.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 13113101033 its reverse (33010131131), we get a palindrome (46123232164).
The spelling of 13113101033 in words is "thirteen billion, one hundred thirteen million, one hundred one thousand, thirty-three".
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