13113101223223 has 4 divisors (see below), whose sum is σ = 13233404904280. Its totient is φ = 12992797542168.

The previous prime is 13113101223181. The next prime is 13113101223323. The reversal of 13113101223223 is 32232210131131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13113101223223 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113101223323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60151840365 + ... + 60151840582.

It is an arithmetic number, because the mean of its divisors is an integer number (3308351226070).

Almost surely, 2^{13113101223223} is an apocalyptic number.

13113101223223 is a deficient number, since it is larger than the sum of its proper divisors (120303681057).

13113101223223 is a wasteful number, since it uses less digits than its factorization.

13113101223223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120303681056.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13113101223223 its reverse (32232210131131), we get a palindrome (45345311354354).

The spelling of 13113101223223 in words is "thirteen trillion, one hundred thirteen billion, one hundred one million, two hundred twenty-three thousand, two hundred twenty-three".