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13113102113 = 531032402107
BaseRepresentation
bin11000011011001101…
…00000111100100001
31020211212121121101122
430031212200330201
5203323423231423
610005111142025
7642645346256
oct141546407441
936755547348
1013113102113
11561a005781
12265b674915
13130c952027
148c57ab42d
1551b3438c8
hex30d9a0f21

13113102113 has 8 divisors (see below), whose sum is σ = 13490238528. Its totient is φ = 12740770224.

The previous prime is 13113102097. The next prime is 13113102151. The reversal of 13113102113 is 31120131131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13113102113 - 24 = 13113102097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13113102091 and 13113102100.

It is not an unprimeable number, because it can be changed into a prime (13113102313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1195595 + ... + 1206512.

It is an arithmetic number, because the mean of its divisors is an integer number (1686279816).

Almost surely, 213113102113 is an apocalyptic number.

It is an amenable number.

13113102113 is a deficient number, since it is larger than the sum of its proper divisors (377136415).

13113102113 is a wasteful number, since it uses less digits than its factorization.

13113102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2402263.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13113102113 its reverse (31120131131), we get a palindrome (44233233244).

The spelling of 13113102113 in words is "thirteen billion, one hundred thirteen million, one hundred two thousand, one hundred thirteen".

Divisors: 1 53 103 5459 2402107 127311671 247417021 13113102113