131131023331999 has 2 divisors, whose sum is σ = 131131023332000. Its totient is φ = 131131023331998.

The previous prime is 131131023331961. The next prime is 131131023332011. The reversal of 131131023331999 is 999133320131131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131131023331999 - 2³⁵ = 131096663593631 is a prime.

It is a super-2 number, since 2×131131023331999² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131131023331939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65565511665999 + 65565511666000.

It is an arithmetic number, because the mean of its divisors is an integer number (65565511666000).

Almost surely, 2^{131131023331999} is an apocalyptic number.

131131023331999 is a deficient number, since it is larger than the sum of its proper divisors (1).

131131023331999 is an equidigital number, since it uses as much as digits as its factorization.

131131023331999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 354294, while the sum is 49.

The spelling of 131131023331999 in words is "one hundred thirty-one trillion, one hundred thirty-one billion, twenty-three million, three hundred thirty-one thousand, nine hundred ninety-nine".