Base | Representation |
---|---|
bin | 11101110100001101010010… |
… | …000100001001011011101111 |
3 | 122012022000002110221122222201 |
4 | 131310031102010021123233 |
5 | 114141422313433124403 |
6 | 1142520432133122331 |
7 | 36422622000336343 |
oct | 3564152204113357 |
9 | 565260073848881 |
10 | 131131023333103 |
11 | 3886739a102592 |
12 | 1285a0a24893a7 |
13 | 58227aa741ca1 |
14 | 2454abd973623 |
15 | 102604391321d |
hex | 7743521096ef |
131131023333103 has 4 divisors (see below), whose sum is σ = 132977939154768. Its totient is φ = 129284107511440.
The previous prime is 131131023333071. The next prime is 131131023333119. The reversal of 131131023333103 is 301333320131131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131131023333103 - 25 = 131131023333071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131131023333203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 923457910726 + ... + 923457910867.
It is an arithmetic number, because the mean of its divisors is an integer number (33244484788692).
Almost surely, 2131131023333103 is an apocalyptic number.
131131023333103 is a deficient number, since it is larger than the sum of its proper divisors (1846915821665).
131131023333103 is an equidigital number, since it uses as much as digits as its factorization.
131131023333103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1846915821664.
The product of its (nonzero) digits is 4374, while the sum is 28.
Adding to 131131023333103 its reverse (301333320131131), we get a palindrome (432464343464234).
The spelling of 131131023333103 in words is "one hundred thirty-one trillion, one hundred thirty-one billion, twenty-three million, three hundred thirty-three thousand, one hundred three".
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