13113104243 has 4 divisors (see below), whose sum is σ = 13118785680. Its totient is φ = 13107422808.

The previous prime is 13113104237. The next prime is 13113104269. The reversal of 13113104243 is 34240131131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34240131131 = 337 ⋅101602763.

It is a cyclic number.

It is not a de Polignac number, because 13113104243 - 2⁴ = 13113104227 is a prime.

It is a super-3 number, since 3×13113104243³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13113104273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2837255 + ... + 2841872.

It is an arithmetic number, because the mean of its divisors is an integer number (3279696420).

Almost surely, 2^13113104243 is an apocalyptic number.

13113104243 is a deficient number, since it is larger than the sum of its proper divisors (5681437).

13113104243 is an equidigital number, since it uses as much as digits as its factorization.

13113104243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5681436.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13113104243 its reverse (34240131131), we get a palindrome (47353235374).

The spelling of 13113104243 in words is "thirteen billion, one hundred thirteen million, one hundred four thousand, two hundred forty-three".