13113110301 has 4 divisors (see below), whose sum is σ = 17484147072. Its totient is φ = 8742073532.

The previous prime is 13113110287. The next prime is 13113110303. The reversal of 13113110301 is 10301131131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13113110301 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113110303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185518381 + ... + 2185518386.

It is an arithmetic number, because the mean of its divisors is an integer number (4371036768).

Almost surely, 2^13113110301 is an apocalyptic number.

It is an amenable number.

13113110301 is a deficient number, since it is larger than the sum of its proper divisors (4371036771).

13113110301 is an equidigital number, since it uses as much as digits as its factorization.

13113110301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4371036770.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 13113110301 its reverse (10301131131), we get a palindrome (23414241432).

The spelling of 13113110301 in words is "thirteen billion, one hundred thirteen million, one hundred ten thousand, three hundred one".