Base | Representation |
---|---|
bin | 11000011011001101… |
… | …00010111110000011 |
3 | 1020211212122000202200 |
4 | 30031212202332003 |
5 | 203323424013103 |
6 | 10005111244243 |
7 | 642645412401 |
oct | 141546427603 |
9 | 36755560680 |
10 | 13113110403 |
11 | 561a010a28 |
12 | 265b679683 |
13 | 130c955a33 |
14 | 8c57b0471 |
15 | 51b3460a3 |
hex | 30d9a2f83 |
13113110403 has 48 divisors (see below), whose sum is σ = 19717416576. Its totient is φ = 8391813120.
The previous prime is 13113110383. The next prime is 13113110407. The reversal of 13113110403 is 30401131131.
13113110403 is a `hidden beast` number, since 1 + 311 + 311 + 0 + 40 + 3 = 666.
13113110403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13113110403 - 25 = 13113110371 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13113110407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 15300751 + ... + 15301607.
It is an arithmetic number, because the mean of its divisors is an integer number (410779512).
Almost surely, 213113110403 is an apocalyptic number.
13113110403 is a deficient number, since it is larger than the sum of its proper divisors (6604306173).
13113110403 is a wasteful number, since it uses less digits than its factorization.
13113110403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1564 (or 1561 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 13113110403 its reverse (30401131131), we get a palindrome (43514241534).
The spelling of 13113110403 in words is "thirteen billion, one hundred thirteen million, one hundred ten thousand, four hundred three".
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