Base | Representation |
---|---|
bin | 11000011011001101… |
… | …00010111110000111 |
3 | 1020211212122000202211 |
4 | 30031212202332013 |
5 | 203323424013112 |
6 | 10005111244251 |
7 | 642645412405 |
oct | 141546427607 |
9 | 36755560684 |
10 | 13113110407 |
11 | 561a010a31 |
12 | 265b679687 |
13 | 130c955a37 |
14 | 8c57b0475 |
15 | 51b3460a7 |
hex | 30d9a2f87 |
13113110407 has 2 divisors, whose sum is σ = 13113110408. Its totient is φ = 13113110406.
The previous prime is 13113110383. The next prime is 13113110447. The reversal of 13113110407 is 70401131131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13113110407 - 227 = 12978892679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13113110447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556555203 + 6556555204.
It is an arithmetic number, because the mean of its divisors is an integer number (6556555204).
Almost surely, 213113110407 is an apocalyptic number.
13113110407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113110407 is an equidigital number, since it uses as much as digits as its factorization.
13113110407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 13113110407 its reverse (70401131131), we get a palindrome (83514241538).
The spelling of 13113110407 in words is "thirteen billion, one hundred thirteen million, one hundred ten thousand, four hundred seven".
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