Base | Representation |
---|---|
bin | 111101000100000000… |
… | …1011111001110100011 |
3 | 110112110202022121021011 |
4 | 1322020001133032203 |
5 | 4122024031012212 |
6 | 140124002441351 |
7 | 12321360022021 |
oct | 1721001371643 |
9 | 415422277234 |
10 | 131131110307 |
11 | 5068110303a |
12 | 214b7663257 |
13 | c49a328982 |
14 | 64bd7c5711 |
15 | 36272e24a7 |
hex | 1e8805f3a3 |
131131110307 has 2 divisors, whose sum is σ = 131131110308. Its totient is φ = 131131110306.
The previous prime is 131131110301. The next prime is 131131110323. The reversal of 131131110307 is 703011131131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131131110307 is a prime.
It is not a weakly prime, because it can be changed into another prime (131131110301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65565555153 + 65565555154.
It is an arithmetic number, because the mean of its divisors is an integer number (65565555154).
Almost surely, 2131131110307 is an apocalyptic number.
131131110307 is a deficient number, since it is larger than the sum of its proper divisors (1).
131131110307 is an equidigital number, since it uses as much as digits as its factorization.
131131110307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 189, while the sum is 22.
Adding to 131131110307 its reverse (703011131131), we get a palindrome (834142241438).
The spelling of 131131110307 in words is "one hundred thirty-one billion, one hundred thirty-one million, one hundred ten thousand, three hundred seven".
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