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13113119 is a prime number
BaseRepresentation
bin110010000001…
…011100011111
3220200012211002
4302001130133
511324104434
61145020515
7216313445
oct62013437
926605732
1013113119
117447098
12448473b
132941856
141a54b95
15124057e
hexc8171f

13113119 has 2 divisors, whose sum is σ = 13113120. Its totient is φ = 13113118.

The previous prime is 13113091. The next prime is 13113127. The reversal of 13113119 is 91131131.

13113119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13113119 is a prime.

It is a super-2 number, since 2×131131192 = 343907779816322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13113119.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13113319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556559 + 6556560.

It is an arithmetic number, because the mean of its divisors is an integer number (6556560).

Almost surely, 213113119 is an apocalyptic number.

13113119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113119 is an equidigital number, since it uses as much as digits as its factorization.

13113119 is an evil number, because the sum of its binary digits is even.

The product of its digits is 81, while the sum is 20.

The square root of 13113119 is about 3621.2040815176. The cubic root of 13113119 is about 235.8135017543.

The spelling of 13113119 in words is "thirteen million, one hundred thirteen thousand, one hundred nineteen".