Base | Representation |
---|---|
bin | 10011000101010000010… |
… | …010111000011001011011 |
3 | 11122100201121011022201111 |
4 | 103011100102320121123 |
5 | 132441031402332110 |
6 | 2442224122201151 |
7 | 163511352245665 |
oct | 23052022703133 |
9 | 4570647138644 |
10 | 1311312152155 |
11 | 466140584575 |
12 | 1921839531b7 |
13 | 9686b8b5bb5 |
14 | 47679ab3535 |
15 | 2419c0c3e8a |
hex | 131504b865b |
1311312152155 has 16 divisors (see below), whose sum is σ = 1630655472384. Its totient is φ = 1011259146240.
The previous prime is 1311312152089. The next prime is 1311312152177. The reversal of 1311312152155 is 5512512131131.
It is a de Polignac number, because none of the positive numbers 2k-1311312152155 is a prime.
It is a super-2 number, since 2×13113121521552 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16419462 + ... + 16499131.
It is an arithmetic number, because the mean of its divisors is an integer number (101915967024).
Almost surely, 21311312152155 is an apocalyptic number.
1311312152155 is a deficient number, since it is larger than the sum of its proper divisors (319343320229).
1311312152155 is a wasteful number, since it uses less digits than its factorization.
1311312152155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32918886.
The product of its digits is 4500, while the sum is 31.
Adding to 1311312152155 its reverse (5512512131131), we get a palindrome (6823824283286).
The spelling of 1311312152155 in words is "one trillion, three hundred eleven billion, three hundred twelve million, one hundred fifty-two thousand, one hundred fifty-five".
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