1311312193 has 2 divisors, whose sum is σ = 1311312194. Its totient is φ = 1311312192.

The previous prime is 1311312139. The next prime is 1311312209. The reversal of 1311312193 is 3912131131.

Together with previous prime (1311312139) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1311308944 + 3249 = 36212^2 + 57^2 .

It is an emirp because it is prime and its reverse (3912131131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311312193 - 2¹⁷ = 1311181121 is a prime.

It is not a weakly prime, because it can be changed into another prime (1011312193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655656096 + 655656097.

It is an arithmetic number, because the mean of its divisors is an integer number (655656097).

Almost surely, 2^1311312193 is an apocalyptic number.

It is an amenable number.

1311312193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311312193 is an equidigital number, since it uses as much as digits as its factorization.

1311312193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 486, while the sum is 25.

The square root of 1311312193 is about 36212.0448607918. The cubic root of 1311312193 is about 1094.5493980799.

The spelling of 1311312193 in words is "one billion, three hundred eleven million, three hundred twelve thousand, one hundred ninety-three".