Base | Representation |
---|---|
bin | 1011111011010010001110… |
… | …0101111110000111011011 |
3 | 1201102121021201220101120012 |
4 | 2332310203211332013123 |
5 | 3204321143332423003 |
6 | 43520031222352135 |
7 | 2522251433362034 |
oct | 276644345760733 |
9 | 51377251811505 |
10 | 13113132311003 |
11 | 41a628037048a |
12 | 15794b558b64b |
13 | 7417420b418a |
14 | 334971213a8b |
15 | 17b18175b8d8 |
hex | bed2397e1db |
13113132311003 has 4 divisors (see below), whose sum is σ = 13113154321128. Its totient is φ = 13113110300880.
The previous prime is 13113132310991. The next prime is 13113132311011. The reversal of 13113132311003 is 30011323131131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13113132311003 - 216 = 13113132245467 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13113132311003.
It is not an unprimeable number, because it can be changed into a prime (13113132311033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10085801 + ... + 11311482.
It is an arithmetic number, because the mean of its divisors is an integer number (3278288580282).
Almost surely, 213113132311003 is an apocalyptic number.
13113132311003 is a deficient number, since it is larger than the sum of its proper divisors (22010125).
13113132311003 is an equidigital number, since it uses as much as digits as its factorization.
13113132311003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22010124.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 13113132311003 its reverse (30011323131131), we get a palindrome (43124455442134).
The spelling of 13113132311003 in words is "thirteen trillion, one hundred thirteen billion, one hundred thirty-two million, three hundred eleven thousand, three".
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