1311314131132 has 12 divisors (see below), whose sum is σ = 2295065915296. Its totient is φ = 655581012480.

The previous prime is 1311314131117. The next prime is 1311314131139. The reversal of 1311314131132 is 2311314131131.

It is a junction number, because it is equal to n+sod(n) for n = 1311314131097 and 1311314131106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311314131139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18974469 + ... + 19043452.

Almost surely, 2^{1311314131132} is an apocalyptic number.

It is an amenable number.

1311314131132 is a deficient number, since it is larger than the sum of its proper divisors (983751784164).

1311314131132 is a wasteful number, since it uses less digits than its factorization.

1311314131132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38026548 (or 38026546 counting only the distinct ones).

The product of its digits is 648, while the sum is 25.

Adding to 1311314131132 its reverse (2311314131131), we get a palindrome (3622628262263).

Subtracting 1311314131132 from its reverse (2311314131131), we obtain a palindrome (999999999999).

The spelling of 1311314131132 in words is "one trillion, three hundred eleven billion, three hundred fourteen million, one hundred thirty-one thousand, one hundred thirty-two".