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131132013031 = 719719040513
BaseRepresentation
bin111101000100000010…
…0111011100111100111
3110112110211000110120101
41322020010323213213
54122024243404111
6140124034044531
712321400501615
oct1721004734747
9415424013511
10131132013031
115068166a298
12214b7a19747
13c49a583826
1464bd97c6b5
15362741ebc1
hex1e8813b9e7

131132013031 has 8 divisors (see below), whose sum is σ = 134349866784. Its totient is φ = 127952240640.

The previous prime is 131132013017. The next prime is 131132013041. The reversal of 131132013031 is 130310231131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131132013031 - 211 = 131132010983 is a prime.

It is a super-2 number, since 2×1311320130312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131132013041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9513370 + ... + 9527143.

It is an arithmetic number, because the mean of its divisors is an integer number (16793733348).

Almost surely, 2131132013031 is an apocalyptic number.

131132013031 is a deficient number, since it is larger than the sum of its proper divisors (3217853753).

131132013031 is an equidigital number, since it uses as much as digits as its factorization.

131132013031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19040681.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131132013031 its reverse (130310231131), we get a palindrome (261442244162).

The spelling of 131132013031 in words is "one hundred thirty-one billion, one hundred thirty-two million, thirteen thousand, thirty-one".

Divisors: 1 71 97 6887 19040513 1351876423 1846929761 131132013031