Base | Representation |
---|---|
bin | 10011000101010000110… |
… | …001010111100110111110 |
3 | 11122100202011012100220112 |
4 | 103011100301113212332 |
5 | 132441040424104233 |
6 | 2442225005350022 |
7 | 163511510213522 |
oct | 23052061274676 |
9 | 4570664170815 |
10 | 1311320144318 |
11 | 466145043168 |
12 | 192186568312 |
13 | 968704538a2 |
14 | 4767ab93d82 |
15 | 2419cb52048 |
hex | 13150c579be |
1311320144318 has 4 divisors (see below), whose sum is σ = 1966980216480. Its totient is φ = 655660072158.
The previous prime is 1311320144317. The next prime is 1311320144333. The reversal of 1311320144318 is 8134410231131.
It is a semiprime because it is the product of two primes.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311320144317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327830036078 + ... + 327830036081.
It is an arithmetic number, because the mean of its divisors is an integer number (491745054120).
Almost surely, 21311320144318 is an apocalyptic number.
1311320144318 is a deficient number, since it is larger than the sum of its proper divisors (655660072162).
1311320144318 is an equidigital number, since it uses as much as digits as its factorization.
1311320144318 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 655660072161.
The product of its (nonzero) digits is 6912, while the sum is 32.
Adding to 1311320144318 its reverse (8134410231131), we get a palindrome (9445730375449).
The spelling of 1311320144318 in words is "one trillion, three hundred eleven billion, three hundred twenty million, one hundred forty-four thousand, three hundred eighteen".
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