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1311320144318 = 2655660072159
BaseRepresentation
bin10011000101010000110…
…001010111100110111110
311122100202011012100220112
4103011100301113212332
5132441040424104233
62442225005350022
7163511510213522
oct23052061274676
94570664170815
101311320144318
11466145043168
12192186568312
13968704538a2
144767ab93d82
152419cb52048
hex13150c579be

1311320144318 has 4 divisors (see below), whose sum is σ = 1966980216480. Its totient is φ = 655660072158.

The previous prime is 1311320144317. The next prime is 1311320144333. The reversal of 1311320144318 is 8134410231131.

It is a semiprime because it is the product of two primes.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311320144317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327830036078 + ... + 327830036081.

It is an arithmetic number, because the mean of its divisors is an integer number (491745054120).

Almost surely, 21311320144318 is an apocalyptic number.

1311320144318 is a deficient number, since it is larger than the sum of its proper divisors (655660072162).

1311320144318 is an equidigital number, since it uses as much as digits as its factorization.

1311320144318 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655660072161.

The product of its (nonzero) digits is 6912, while the sum is 32.

Adding to 1311320144318 its reverse (8134410231131), we get a palindrome (9445730375449).

The spelling of 1311320144318 in words is "one trillion, three hundred eleven billion, three hundred twenty million, one hundred forty-four thousand, three hundred eighteen".

Divisors: 1 2 655660072159 1311320144318